The product of two numbers is 2028 and their HCF is 13. The number of such pairs is :
The product of two numbers is 2028 and their HCF is 13. The number of such pairs is :
[A]1
[B]2
[C]3
[D]4
2
Here, HCF = 13
Let the numbers be 13x and 13y, where x and y are prime to each other.
Now, 13x 
The opposite pairs are : (1, 12), (3, 4), (2, 6)
But the 2 and 6 are not co-prime.
So, required no. of pairs = 2
Hence option [B] is correct answer.
