The diagonal of a square A is (a+b). The diagonal of a square whose are is twice the area of square A, is

The diagonal of a square A is (a+b). The diagonal of a square whose are is twice the area of square A, is [A]$latex \sqrt{2}(a-b)$ [B]$latex \sqrt{2}(a+b)$ [C]$latex 2(a+b)^{2}$ [D]$latex 2(a+b)$ Show Answer $latex \mathbf{\sqrt{2}(a+b)}$ Area of the square A ..

Isak Chisi Swu, founder of NSCN (IM) passes away

Naga leader and founder of Nationalist Socialist Council of Nagaland (Isak-Muivah), Isak Chisi Swu passed away in Delhi. He was 86. As a Naga leader he had led one of the worst insurgencies in the North-East India for almost three ..

Month: Current Affairs - June, 2016

CSIR-CIMFR, Coal supplying companies ink MoU for coal quality analysis

The CSIR-Central Institute of Mining and Fuel Research (CSIR-CIMFR) has signed a Memorandum of Understanding (MoU) with coal supplying companies and power utilities for quality analysis of coal supplied. The MoU was signed in presence of Uniin Science and Technology ..

Month: Current Affairs - June, 2016

India shooter Sanjeev Rajput wins silver medal in ISSF World Cup

Ace Indian shooter Sanjeev Rajput has won the silver medal in men’s 50-metre rifle 3 position event of the ISSF World Cup held in Baku, Ajerbaijan. Rajput shot 456.9 points to win the silver medal. Croatia’s Petar Gorsa won the ..

Month: Current Affairs - June, 2016

The radius of the incircle of the equilateral triangle having each side 6 cm is

The radius of the incircle of the equilateral triangle having each side 6 cm is [A]$latex 3cm$ [B]$latex \sqrt{3}cm$ [C]$latex 2\sqrt{3}cm$ [D]$latex 6\sqrt{3}cm$ Show Answer $latex \mathbf{\sqrt{3}cm}$ E = In-center, AD ⊥ BC AB = 6 cm, BD = 3 ..

G is the centroid in the equilateral △ ABC. If AB = 10 cm then length of AG is :

G is the centroid in the equilateral △ ABC. If AB = 10 cm then length of AG is : [A]$latex \frac{20\sqrt{3}}{3}cm&s=1$ [B]$latex 10\sqrt{3}cm$ [C]$latex \frac{10\sqrt{3}}{3}cm&s=1$ [D]$latex 5\sqrt{3}cm$ Show Answer $latex \mathbf{\frac{10\sqrt{3}}{3}cm}&s=1$ AB = 10cm BD = 5 cm ∠ADB ..