If two items of A is equal to three times of B and also equal to four times of C, then A : B : C is :
If two items of A is equal to three times of B and also equal to four times of C, then A : B : C is :
[A]2 : 3 : 5
[B]3 : 4 : 2
[C]4 : 6 : 3
[D]6 : 4 : 3
6 : 4 : 3
According to the question,
$latex 2A = 3B$
$latex => B = \frac{2}{3}A&s=1$
and $latex 2A = 4C$
$latex => C = \frac{1}{2}A&s=1$
$latex \therefore A : B : C = A : \frac{2}{3}A : \frac{1}{2}A&s=1$
$latex = 1 : \frac{2}{3}: \frac{1}{2} = 6:4:3&s=1$
Hence option [D] is correct answer.