The HCF of two numbers is 16 and their LCM is 160. If one of the number is 32, then the other number is:

The HCF of two numbers is 16 and their LCM is 160. If one of the number is 32, then the other number is:
[A]96
[B]48
[C]112
[D]80

80
We know that, First number $latex \times$ Second number = LCM $latex \times$ HCF
$latex =>$Second Number $latex =\frac{16\times 160}{32}=80&s=1$
Hence option [D] is the right answer.


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