The HCF of two numbers 12906 and 14818 is 487. Their LCM is :

The HCF of two numbers 12906 and 14818 is 487. Their LCM is :
[A]600129
[B]800172
[C]400086
[D]200043

400086
Because product of two numbers = HCF $latex \times$ LCM
$latex =>$ 12906 $latex \times$ 14818 = LCM $latex \times$ 478
$latex => LCM$ = $latex \frac{12906\times 14818}{478}=400086&s=1$
Hence option [C] is the right answer.


Leave a Reply

Your email address will not be published. Required fields are marked *