The HCF and LCM of two numbers are 12 and 336 respectively. If one of the number is 84, the other is :

The HCF and LCM of two numbers are 12 and 336 respectively. If one of the number is 84, the other is :
[A]48
[B]36
[C]96
[D]76

48
First Number $latex \times$ Second Number = HCF $latex \times$ LCM
=> 84 $latex \times$ second number = 12 $latex \times$ 336
Since second number = $latex \frac{12\times 336}{84} = 48&s=1$
Hence option [A] is the right answer.


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