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The diagonal of a square A is (a+b). The diagonal of a square whose are is twice the area of square A, is

The diagonal of a square A is (a+b). The diagonal of a square whose are is twice the area of square A, is
[A]\sqrt{2}(a-b)
[B]\sqrt{2}(a+b)
[C]2(a+b)^{2}
[D]2(a+b)

\mathbf{\sqrt{2}(a+b)}
Area of the square A = \frac{\left ( diagonal \right )^{2}}{2}= \frac{\left ( a+b \right )^{2}}{2}
Area of the new square
= \frac{\left ( a+b \right )^{2}}{2}\times 2 = \left ( a+b \right )^{2}
=> side = (a+b)
\therefore Diagonal = \sqrt{2}\times side
= \sqrt{2}(a+b)
Hence option [B] is the right answer.

Originally written on June 29, 2016 and last modified on June 29, 2016.
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