The circular measure of an angle of an isoceles triangle is 5π/9. Circular measure of one of the other angles must be

The circular measure of an angle of an isoceles triangle is 5π/9. Circular measure of one of the other angles must be
[A]\frac{4\pi }{9}
[B]\frac{2\pi }{9}
[C]\frac{5\pi }{9}
[D]\frac{5\pi }{18}

\frac{2 \pi}{9}
Sum of remaining two angles = \pi -\frac{5\pi }{9}=\frac{4\pi}{9}
∴ Each angle = \frac{1}{2}\times \frac{4\pi }{9}=\frac{2\pi }{9}
Hence option [B] is the right answer.

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