If A and B together can complete a work in 18 days, A and C together in 12 days and B and C together in 9 days, then in how many days B alone can do the work?

If A and B together can complete a work in 18 days, A and C together in 12 days and B and C together in 9 days, then in how many days B alone can do the work?
[A]18 days
[B]24 days
[C]30 days
[D]40 days

24 days
(A + B)’s 1 day’s work = \frac{1}{18}
(B + C)’s 1 day’s work = \frac{1}{9}
(C + A)’s 1 day’s work = \frac{1}{12}
On adding all above equations, we get
2 (A +B + C)’s 1 day’s work = \frac{1}{18} + \frac{1}{9} + \frac{1}{12} = \frac{2+4+3}{36} = \frac{9}{36} = \frac{1}{4}
∴ (A + B + C)’s 1 day’s work = \frac{1}{8}
Now, B’s 1 day’s work = (A + B + C)’s 1 day’s work – (A + C)’s 1 day’s work
= \frac{1}{8}-\frac{1}{12}=\frac{3-2}{24}=\frac{1}{24}
Hence B alone can do the work in 24 days. So option [B] is correct answer.

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