The LCM of two numbers is 864 and their HCF is 144. If one of the number is 288, the other number is :

The LCM of two numbers is 864 and their HCF is 144. If one of the number is 288, the other number is :
[A]144
[B]432
[C]1296
[D]576

432
Required number = $latex \frac{HCF\times LCM}{First number}&s=1$
$latex =\frac{864\times 144}{288} = 432&s=1$
So the second number is 432.
Hence option [B] is the right answer.


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