A and B can do a work in 12 days, B and C in 15 days and C and A in 20 days. If A, B and C work together, they will complete the work in :

A and B can do a work in 12 days, B and C in 15 days and C and A in 20 days. If A, B and C work together, they will complete the work in :
[A]15\frac{2}{3} days
[B]5 days
[C]10 days
[D]7\frac{5}{6} days

10 days
According to question,
A and B can do a work in 12 days
∴ (A + B)’s one day’s work = \frac{1}{12}
Similarly, (B + C)’s one day’s work = \frac{1}{15}
and (C + A)’s one day’s work = \frac{1}{20}
On adding all three,
∴ 2 (A + B + C)’s one day’s work = \frac{1}{12}+ \frac{1}{15}+ \frac{1}{20}
= \frac{10+8+6}{120} = \frac{1}{5}
and (A + B + C)’s one day’s work = \frac{1}{10}
∴ A, B and C together can complete the work in 10 days.

1 Comment

  1. Harpreet

    March 31, 2018 at 3:32 pm

    Oh.. Quite simple… I got it

    Reply

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