The HCF and product of two numbers are 15 and 6300 respectively. The number of possible pairs of the number is :
The HCF and product of two numbers are 15 and 6300 respectively. The number of possible pairs of the number is :
[A]3
[B]1
[C]4
[D]2
2
Let the number be 15x and 15y, where x and y are co-prime.
Since 15x $latex \times $15y = 6300
$latex => xy = \frac{6300}{15\times 15} = 28&s=1$
So, two pairs are (7, 4) and (14, 2)
Hence the right option is [D].