The least number which when divided by 4, 5 and 6 leaves remainder 1, 2 and 3 respectively, is : [A] 57[B] 59[C] 61[D] 63Show AnswerCorrect Answer: A [57]Notes:Here 4 – 1 = 3, 5 – 2 = 3, 6 – 3 = 3 ∴ The required Number = LCM of (4, 5, 6) – 3 = 60 – 3 = 57. Hence option [A] is correct answer.Advertisement Kindly help us to keep GKToday updated and error free. Use this form to report error or outdated information in questions. We shall rectify asap...
