Q. The least number which when divided by 4, 5 and 6 leaves remainder 1, 2 and 3 respectively, is :
Answer: 57
Notes: Here 4 - 1 = 3, 5 - 2 = 3, 6 - 3 = 3 ∴ The required Number = LCM of (4, 5, 6) - 3 = 60 - 3 = 57. Hence option [A] is correct answer.

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