The product of two numbers is 2028 and their HCF is 13. The number of such pairs is :
Q. The product of two numbers is 2028 and their HCF is 13. The number of such pairs is :
Answer: 2
Notes: Here, HCF = 13 Let the numbers be 13x and 13y, where x and y are prime to each other. Now, 13x $latex \times$ 13y = 2028 $latex => xy = \frac{2028}{13\times 13} = 12&s=1$ The opposite pairs are : (1, 12), (3, 4), (2, 6) But the 2 and 6 are not co-prime. So, required no. of pairs = 2 Hence option [B] is correct answer.