The smallest number, which when divided by 12 and 16 leaves remaining 5 and 9 respectively, is :

The smallest number, which when divided by 12 and 16 leaves remaining 5 and 9 respectively, is :
[A]29
[B]39
[C]41
[D]55

41
Here because, 12 – 5 = 7, 16 – 9 = 7
Since required number = LCM of 12 and 16 – 7
= 48 – 7 = 41.
Hence option [C] is correct answer.

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