The smallest number, which when divided by 12 and 16 leaves remaining 5 and 9 respectively, is :

[A]29

[B]39

[C]41

[D]55

**41**

Here because, 12 – 5 = 7, 16 – 9 = 7

Since required number = LCM of 12 and 16 – 7

= 48 – 7 = 41.

Hence option [C] is correct answer.