# Find the HCF of 84, 121, 140

Find the HCF of 84, 121, 140
[A]10
[B]14
[C]6
[D]12

14
$\because 84=2^{2}\times 3\times 7$
$126=2\times3^{2}\times7$
and $140=2^{2}\times 5\times 7$
$\therefore HCF = 2\times 7=14$
Hence option [B] Is the right answer.