Aptitude Question ID : 94393

A person started his journey in the morning. At 11 am he covered \frac{3}{8} of the journey and on the same day at 4.30 pm he covered \frac{5}{6} of the journey. He started his journey at :
[A]3.30 am
[B]6.00 am
[C]6.30 am
[D]7.00 am

6.30 am
Difference of time = 4.30 pm - 11 am
= 5\frac{1}{2}hours = \frac{11}{2}hours
Distance covered in \frac{11}{2} hours = \frac{5}{6} - \frac{3}{8} = \frac{20-9}{24} = \frac{11}{24}part
\because \frac{11}{24} part of the journey is covered in \frac{11}{2} hours
=> \frac{3}{8} part of the journey is covered in = \frac{11}{2}\times \frac{24}{11}\times \frac{3}{8} = \frac{9}{2} hours
= 4\frac{1}{2}hours
Clearly the person started at 6.30 am
Hence option [C] is correct answer.

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