# Aptitude Question ID : 94393

A person started his journey in the morning. At 11 am he covered $\frac{3}{8}$ of the journey and on the same day at 4.30 pm he covered $\frac{5}{6}$ of the journey. He started his journey at :
[A]3.30 am
[B]6.00 am
[C]6.30 am
[D]7.00 am

6.30 am
Difference of time $= 4.30 pm - 11 am$
$= 5\frac{1}{2}hours = \frac{11}{2}hours$
Distance covered in $\frac{11}{2}$ hours $= \frac{5}{6} - \frac{3}{8} = \frac{20-9}{24} = \frac{11}{24}part$
$\because \frac{11}{24}$ part of the journey is covered in $\frac{11}{2}$ hours
$=> \frac{3}{8}$ part of the journey is covered in $= \frac{11}{2}\times \frac{24}{11}\times \frac{3}{8} = \frac{9}{2} hours$
$= 4\frac{1}{2}hours$
Clearly the person started at 6.30 am
Hence option [C] is correct answer.