6.30 am
Difference of time $latex = 4.30 pm – 11 am$
$latex = 5\frac{1}{2}hours = \frac{11}{2}hours&s=1$
Distance covered in $latex \frac{11}{2}&s=1$ hours $latex = \frac{5}{6} – \frac{3}{8} = \frac{20-9}{24} = \frac{11}{24}part&s=1$
$latex \because \frac{11}{24}&s=1$ part of the journey is covered in $latex \frac{11}{2}&s=1$ hours
$latex => \frac{3}{8}&s=1$ part of the journey is covered in $latex = \frac{11}{2}\times \frac{24}{11}\times \frac{3}{8} = \frac{9}{2} hours&s=1$
$latex = 4\frac{1}{2}hours&s=1$
Clearly the person started at 6.30 am
Hence option [C] is correct answer.