# Of the three numbers, second is twice the first and is also thrice the third. If the average of the three numbers is 66, find the largest number.

Of the three numbers, second is twice the first and is also thrice the third. If the average of the three numbers is 66, find the largest number.
[A]16
[B]18
[C]15
[D]17

18
Let the the first number be x
Then, second number = 2x and third number = $\frac{2x}{3}$.
$=>x+2x+\frac{2x}{3}=66\times 3$
$=>3x+6x+2x=198$
$=>x=\frac{198}{11}=1$
Hence option [B] is the right answer.