The BF3 molecule exhibits a dipole moment of 0 because its structure comprises of two equal bond dipoles that are oriented in opposite directions, thereby cancelling out each other's effects. Each BF bond consists of one Boron - Fluorine atomic pair. Though each Boron - Fluorine bond is polar, the trigonal planar geometry of BF3 results in a perfectly symmetrical distribution of charge, ensuring that the resultant dipole moment is zero.
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