G is the centroid in the equilateral △ ABC. If AB = 10 cm then length of AG is :
[A] \frac{20\sqrt{3}}{3}cm
[B] 10\sqrt{3}cm
[C] \frac{10\sqrt{3}}{3}cm
[D] 5\sqrt{3}cm

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This question is part of UPSC Prelims Practice and Mock Tests membership programme.

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