Aptitude Question ID : 93627

The mean proportional between $latex (3+\sqrt{2})$ and $latex (12-\sqrt{32})$ is:
[A]$latex 6$
[B]$latex \sqrt{7}$
[C]$latex 2\sqrt{7}$
[D]$latex \frac{15-3\sqrt{2}}{2}&s=1$

$latex \mathbf{2\sqrt{7}}$
Mean Proportional =
$latex => \sqrt{(3+\sqrt{2})(12-\sqrt{32})}$
$latex => \sqrt{(3+\sqrt{2})4(3-\sqrt{2})}$
$latex => 2\sqrt{9-2} = 2\sqrt{7}$
Hence option [C] is the right answer.


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