Aptitude Question ID : 92648

Simplify
$latex \frac{19}{43}\div \frac{1}{2+\frac{1}{3+\frac{1}{1+\frac{1}{4}}}}&s=1$
[A]$latex 1$
[B]$latex \frac{38}{43}&s=1$
[C]$latex \frac{43}{19}&s=1$
[D]$latex \frac{19}{43}&s=1$

1
Given that,
$latex \frac{19}{43}\div \frac{1}{2+\frac{1}{3+\frac{1}{1+\frac{1}{4}}}}&s=1$
$latex = \frac{19}{43}\div \frac{1}{2+\frac{1}{3+\frac{4}{5}}}&s=1$
$latex = \frac{19}{43}\div \frac{1}{2+\frac{5}{19}}&s=1$
$latex = \frac{19}{43}\div \frac{19}{43} = 1&s=1$
Hence option [B] is the right answer.


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