# Aptitude Question ID : 92648

Simplify

$latex \frac{19}{43}\div \frac{1}{2+\frac{1}{3+\frac{1}{1+\frac{1}{4}}}}&s=1$

[A]$latex 1$

[B]$latex \frac{38}{43}&s=1$

[C]$latex \frac{43}{19}&s=1$

[D]$latex \frac{19}{43}&s=1$

**1**

Given that,

$latex \frac{19}{43}\div \frac{1}{2+\frac{1}{3+\frac{1}{1+\frac{1}{4}}}}&s=1$

$latex = \frac{19}{43}\div \frac{1}{2+\frac{1}{3+\frac{4}{5}}}&s=1$

$latex = \frac{19}{43}\div \frac{1}{2+\frac{5}{19}}&s=1$

$latex = \frac{19}{43}\div \frac{19}{43} = 1&s=1$

Hence option [B] is the right answer.