Q. The HCF and product of two numbers are 15 and 6300 respectively. The number of possible pairs of the number is :
Answer: 2
Notes: Let the number be 15x and 15y, where x and y are co-prime. Since 15x $latex \times $15y = 6300 $latex => xy = \frac{6300}{15\times 15} = 28&s=1$ So, two pairs are (7, 4) and (14, 2) Hence the right option is [D]

3