If \frac{\tan +\cot }{\tan -\cot } = 2, (0\leq \theta\leq 90^{\circ}), then the value of \sin \theta is :
[A] 1
[B] \frac{1}{2}
[C] \frac{\sqrt{3}}{2}
[D] \frac{2}{\sqrt{3}}

Show Answer

Advertisement

Quiz Categories