# If the students of a class can be grouped exactly into 6 or 8 or 10, then the minimum number of students in the class must be :

If the students of a class can be grouped exactly into 6 or 8 or 10, then the minimum number of students in the class must be : [A]60 [B]120 [C]180 [D]240 Show Answer 120 Because the required number of students = LCM of 6, 8, 10 = 120. Hence option [B] is correct answer.

# The smallest number, which when divided by 12 and 16 leaves remaining 5 and 9 respectively, is :

The smallest number, which when divided by 12 and 16 leaves remaining 5 and 9 respectively, is : [A]29 [B]39 [C]41 [D]55 Show Answer 41 Here because, 12 – 5 = 7, 16 – 9 = 7 Since required number = LCM of 12 and 16 – 7 = 48 – 7 = 41. Hence […]

# Which is the least number which when double will be exactly divisible by 12, 18, 21 and 30?

Which is the least number which when double will be exactly divisible by 12, 18, 21 and 30? [A]196 [B]630 [C]1260 [D]2520 Show Answer 630 The LCM of 12, 18, 21, 30 is 1260. ∴ The required Number = Hence option [B] is correct answer.

# The least multiple of 13, which on dividing by 4, 5, 6, 7 and 8 leaves remainder 2 in each case is :

The least multiple of 13, which on dividing by 4, 5, 6, 7 and 8 leaves remainder 2 in each case is : [A]840 [B]842 [C]2520 [D]2522 Show Answer 2522 LCM of 4, 5, 6, 7 and 8 = 840. Let require number be 840 K + 2 which is multiple of 13. Least value […]

# The least number which when divided by 4, 5 and 6 leaves remainder 1, 2 and 3 respectively, is :

The least number which when divided by 4, 5 and 6 leaves remainder 1, 2 and 3 respectively, is : [A]57 [B]59 [C]61 [D]63 Show Answer 57 Here 4 – 1 = 3, 5 – 2 = 3, 6 – 3 = 3 ∴ The required Number = LCM of (4, 5, 6) – 3 […]

# Let the least number of six digit which when divided by 4, 6, 10 and 15 leaves in each case same remainder 2 be N. The sum of digit in N is :

Let the least number of six digit which when divided by 4, 6, 10 and 15 leaves in each case same remainder 2 be N. The sum of digit in N is : [A]3 [B]4 [C]5 [D]6 Show Answer 5 LCM of 4, 6, 10, 15 = 60 Least number of 6 digits = 100000 […]

# The least number, which when divided by 12, 15, 20 or 54 leaves a remainder of 4 in each case is :

The least number, which when divided by 12, 15, 20 or 54 leaves a remainder of 4 in each case is : [A]450 [B]454 [C]540 [D]544 Show Answer 544 LCM of 15, 12, 20, 54 = 540 Then number = 540 + 4 = 544 (4 being Remainder) Hence option [D] is correct answer.

# A, B, C start running at the same time and at the same point in the same direction in a circular stadium. A completes a round in 252 seconds, B in 308 seconds and C in 198 seconds. After what time will they meet again at the starting point?

A, B, C start running at the same time and at the same point in the same direction in a circular stadium. A completes a round in 252 seconds, B in 308 seconds and C in 198 seconds. After what time will they meet again at the starting point? [A]26 hours 18 seconds [B]42 hours […]

# The LCM and HCF of two numbers are 44 and 264 respectively. If the first number is divided by 2, the quotient is 44. Then the other number is :

The LCM and HCF of two numbers are 44 and 264 respectively. If the first number is divided by 2, the quotient is 44. Then the other number is : [A]132 [B]147 [C]264 [D]528 Show Answer 132 First Number = 2 44 = 88 ∴ First Number Second Number = HCF LCM => 88 Second […]

# The least number which when divided by 4, 6, 8, 12 and 16 leaves a remainder of 2 in each case is :

The least number which when divided by 4, 6, 8, 12 and 16 leaves a remainder of 2 in each case is : [A]46 [B]48 [C]50 [D]56 Show Answer 50 Because LCM of 4, 6, 8, 12 and 16 is 48 ∴ Required number = 48 + 2 = 50 Hence option [C] is correct […]