Find out the value of
$\frac{(243)^{\frac{n}{5}}.3^{2n+1}}{9^{n}.3^{n-1}}$
[A]$1$
[B]$3^{n}$
[C]$9$
[D]$3$

9
Given Expression,
$= \frac{(243)^{\frac{n}{5}}.3^{2n+1}}{9^{n}.3^{n-1}}$
$=> \frac{(3^{5})^{\frac{n}{5}}\times 3^{2n+1}}{(3^{2})^{n}\times 3^{n-1}} = \frac{3^{n}\times 3^{2n+1}}{3^{2n}\times 3^{n-1}}$
$=> \frac{3^{n+2n+1}}{3^{2n+n-1}} = \frac{3^{3n+1}}{3^{3n-1}}$
$=> 3^{3n+1-3n+1} = 3^{2} = 9$
Hence option [C] is the right answer.