The sum of first sixty numbers from one to sixty is divisible by :

The sum of first sixty numbers from one to sixty is divisible by :
[A]13
[B]59
[C]60
[D]61

61
Sum of first 60 numbers
= \frac{60(60+1)}{2} = \frac{60\times 61}{2} = 1830
The number 1830 is divisible by 61.
Hence option [D] is correct answer.

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