The least number which when divided by 4, 6, 8, 12 and 16 leaves a remainder of 2 in each case is :

The least number which when divided by 4, 6, 8, 12 and 16 leaves a remainder of 2 in each case is :
[A]46
[B]48
[C]50
[D]56

50
Because LCM of 4, 6, 8, 12 and 16 is 48
∴ Required number = 48 + 2 = 50
Hence option [C] is correct answer.

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