The least number which when divided by 4, 5 and 6 leaves remainder 1, 2 and 3 respectively, is :

[A]57

[B]59

[C]61

[D]63

**57**

Here 4 – 1 = 3, 5 – 2 = 3, 6 – 3 = 3

∴ The required Number = LCM of (4, 5, 6) – 3

= 60 – 3 = 57.

Hence option [A] is correct answer.