The least number which when divided by 4, 5 and 6 leaves remainder 1, 2 and 3 respectively, is :

The least number which when divided by 4, 5 and 6 leaves remainder 1, 2 and 3 respectively, is :
[A]57
[B]59
[C]61
[D]63

57
Here 4 – 1 = 3, 5 – 2 = 3, 6 – 3 = 3
∴ The required Number = LCM of (4, 5, 6) – 3
= 60 – 3 = 57.
Hence option [A] is correct answer.

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