The least multiple of 13, which on dividing by 4, 5, 6, 7 and 8 leaves remainder 2 in each case is :
[A]840
[B]842
[C]2520
[D]2522

2522
LCM of 4, 5, 6, 7 and 8 = 840.
Let require number be 840 K + 2 which is multiple of 13.
Least value of K for which (840 K + 2) is divisible by 13 is K = 3
∴ Require Number = 840 \times 3 + 2 = 2520 + 2 = 2522.
Hence option [D] is correct answer.