The least multiple of 13, which on dividing by 4, 5, 6, 7 and 8 leaves remainder 2 in each case is :

The least multiple of 13, which on dividing by 4, 5, 6, 7 and 8 leaves remainder 2 in each case is :
[A]840
[B]842
[C]2520
[D]2522

2522
LCM of 4, 5, 6, 7 and 8 = 840.
Let require number be 840 K + 2 which is multiple of 13.
Least value of K for which (840 K + 2) is divisible by 13 is K = 3
∴ Require Number = 840 \times 3 + 2 = 2520 + 2 = 2522.
Hence option [D] is correct answer.

Comments

  • john
    Reply

    how do you know the value of k?

  • hitler
    Reply

    exactly that my point

  • Kavya
    Reply

    What is mean by K and how to came k that place?

  • Sandy chavda
    Reply

    Friends you see option (c) multiply 2522 with 13 answer is 32786 now divide this NUM(32786) by 4,5,6,7,8 but only 4,6,8 is given reminder 2 and friends you Reade question properly. Question say reminder 2 in each case not say every time.so that means only option (c)(2522) is given reminder 2 in case of 4,6,8 no other option given this kind of reminder.so answer is 2522