The least multiple of 13, which on dividing by 4, 5, 6, 7 and 8 leaves remainder 2 in each case is :

[A]840

[B]842

[C]2520

[D]2522

**2522**

LCM of 4, 5, 6, 7 and 8 = 840.

Let require number be 840 K + 2 which is multiple of 13.

Least value of K for which (840 K + 2) is divisible by 13 is K = 3

∴ Require Number = 840 3 + 2 = 2520 + 2 = 2522.

Hence option [D] is correct answer.