Let the least number of six digit which when divided by 4, 6, 10 and 15 leaves in each case same remainder 2 be N. The sum of digit in N is :

[A]3

[B]4

[C]5

[D]6

**5**

LCM of 4, 6, 10, 15 = 60

Least number of 6 digits = 100000

The leats number of 6 digits which is exactly divisible by 60 = 100000 + (60 – 40) = 100020

∴ Required Number = 100020 + 2 = 100022

Hence, the sum of digits = 1 + 0 + 0 + 0 + 2 + 2 = 5

Hence option [C] is correct answer.