Aptitude Question ID : 93812

If \frac{2p}{p^{2} - 2p + 1} = \frac{1}{4}, p\neq 0, then the value of p + \frac{1}{p} is :
[A]4
[B]10
[C]12
[D]5

10
Given Expression :
\frac{2p}{p^{2}-2p+1} = \frac{1}{4}
=> \frac{p^{2}-2p+1}{2p} = 4
=> \frac{p^{2}-2p+1}{p} = 8
=> \frac{p^{2}}{p} - \frac{2p}{p} +\frac{1}{p} = 8
=> p+\frac{1}{p} = 8+2 = 10
Hence option [B] is the right answer.

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