# Aptitude Question ID : 93812

If $\frac{2p}{p^{2} - 2p + 1} = \frac{1}{4}, p\neq 0,$ then the value of $p + \frac{1}{p}$ is :
[A]4
[B]10
[C]12
[D]5

10
Given Expression :
$\frac{2p}{p^{2}-2p+1} = \frac{1}{4}$
$=> \frac{p^{2}-2p+1}{2p} = 4$
$=> \frac{p^{2}-2p+1}{p} = 8$
$=> \frac{p^{2}}{p} - \frac{2p}{p} +\frac{1}{p} = 8$
$=> p+\frac{1}{p} = 8+2 = 10$
Hence option [B] is the right answer.