For an equilateral triangle, the ratio of the in-radius and the ex-radius is:
For an equilateral triangle, the ratio of the in-radius and the ex-radius is:
[A]$latex 1 : 3$
[B]$latex 1 : \sqrt{3}$
[C]$latex 1 : \sqrt{2}$
[D]$latex 1 : 2$
$latex \mathbf{1 : 2}$
In-radius $latex = \frac{side}{2\sqrt{3}}&s=1$
Circum-radius $latex = \frac{side}{\sqrt{3}}&s=1$
∴ Required ratio $latex = \frac{side}{2\sqrt{3}} : \frac{side}{\sqrt{3}}&s=1$
$latex = \sqrt{3} : 2\sqrt{3} = 1 : 2$
Hence option [D] is the right answer.
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Gautam sharma
June 19, 2018 at 8:57 amCircumradius should be used instead of ex-radius