Aptitude Question ID : 94830
The value of
$latex 4-\frac{1}{1+\frac{1}{3+\frac{1}{2+\frac{1}{4}}}}&s=2$ is :
[A]$latex \frac{1}{64}&s=1$
[B]$latex \frac{1}{32}&s=1$
[C]$latex \frac{1}{16}&s=1$
[D]$latex \frac{1}{8}&s=1$
$latex \mathbf{\frac{1}{8}}&s=1$
$latex Expression = 4-\frac{5}{1+\frac{1}{3+\frac{1}{\frac{8+1}{4}}}}&s=2$
$latex = 4-\frac{5}{1+\frac{1}{3+\frac{4}{9}}} = 4-\frac{5}{1+\frac{1}{\frac{27+4}{9}}}&s=2$
$latex = 4-\frac{5}{1+\frac{9}{31}} = 4-\frac{5}{\frac{31+9}{31}}&s=2$
$latex = 4-\frac{5\times 31}{40} = \frac{160-155}{40}&s=2$
$latex = \frac{5}{40} = \frac{1}{8}&s=2$
Hence option [D] is right answer.