Aptitude Question ID : 94817
The value of
$latex 1-\frac{a}{1-\frac{1}{1+\frac{a}{1-a}}}&s=2$ is :
[A]0
[B]1
[C]1 – a
[D]a
0
$latex Expression = 1-\frac{a}{1-\frac{1}{1+\frac{a}{1-a}}}&s=2$
$latex = 1-\frac{a}{1-\frac{1}{\frac{1-a+a}{1-a}}} = 1-\frac{a}{1-\frac{1}{\frac{1}{1-a}}}&s=2$
$latex = 1-\frac{a}{1-\left ( 1-a \right )} = 1-\frac{a}{1-1+a}&s=2$
$latex = 1-1 = 0&s=1$
Hence option [A] is right answer.