Aptitude Question ID : 94721

\frac{13}{48} is equal to :
[A]
\frac{1}{3+\frac{1}{1+\frac{1}{16}}}
[B]
\frac{1}{2+\frac{1}{1+\frac{1}{8}}}
[C]
\frac{1}{3+\frac{1}{1+\frac{1}{1+\frac{1}{8}}}}
[D]
\frac{1}{3+\frac{1}{1+\frac{1}{2+\frac{1}{4}}}}

\mathbf{\frac{1}{3+\frac{1}{1+\frac{1}{2+\frac{1}{4}}}}}
Check through options, by option [D]
\frac{1}{3+\frac{1}{1+\frac{1}{2+\frac{1}{4}}}}
= \frac{1}{3+\frac{1}{1+\frac{1}{\frac{8+1}{4}}}} = \frac{1}{3+\frac{1}{1+\frac{4}{9}}}
= \frac{1}{3+\frac{1}{\frac{9+4}{9}}} = \frac{1}{3+\frac{9}{13}}
= \frac{1}{\frac{39+9}{13}} = \frac{13}{48}
Hence option [D] is right answer.

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