Aptitude Question ID : 94170

The average of x numbers is y^{2} and the average of y numbers is x^{2}. So the average of all the numbers taken together is:
[A]xy
[B]xy^{2}+yx^{2}
[C]\frac{x^{2}+y^{2}}{x+y}
[D]\frac{x^{3}+y^{3}}{x+y}

\mathbf{xy}
Total sum of x numbers = xy^{2}
Total sum of y numbers = yx^{2}
∴ Required Average =
= \frac{xy^{2}+yx^{2}}{x+y}
= \frac{xy(y+x)}{x+y} = xy
Hence option [A] is the right answer.

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