Aptitude Question ID: 107042

\frac{3\sqrt{12}}{2\sqrt{28}}\div \frac{2\sqrt{21}}{\sqrt{98}} is approximately equal to :
[A]1.0727
[B]1.6026
[C]1.0606
[D]1.6007

1.0606
We have to find the approx value of \frac{3\sqrt{12}}{2\sqrt{28}}\div \frac{2\sqrt{21}}{\sqrt{98}}
\frac{3\sqrt{12}}{2\sqrt{28}}\div \frac{2\sqrt{21}}{\sqrt{98}}
=\frac{3\sqrt{12}}{2\sqrt{28}}\times \frac{\sqrt{98}}{2\sqrt{21}}
= \frac{3\times 2\times \sqrt{3}}{2\times 2\times \sqrt{7}}\times \frac{7\times \sqrt{2}}{2\times \sqrt{3}\times \sqrt{7}}
= \frac{3\sqrt{2}}{4} = \frac{3\times 1.414}{4} = 1.0605\approx 1.0606
Hence option [C] is correct answer.

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