$\frac{3\sqrt{12}}{2\sqrt{28}}\div \frac{2\sqrt{21}}{\sqrt{98}}$ is approximately equal to :
[A]1.0727
[B]1.6026
[C]1.0606
[D]1.6007

1.0606
We have to find the approx value of $\frac{3\sqrt{12}}{2\sqrt{28}}\div \frac{2\sqrt{21}}{\sqrt{98}}$
$\frac{3\sqrt{12}}{2\sqrt{28}}\div \frac{2\sqrt{21}}{\sqrt{98}}$
$=\frac{3\sqrt{12}}{2\sqrt{28}}\times \frac{\sqrt{98}}{2\sqrt{21}}$
$= \frac{3\times 2\times \sqrt{3}}{2\times 2\times \sqrt{7}}\times \frac{7\times \sqrt{2}}{2\times \sqrt{3}\times \sqrt{7}}$
$= \frac{3\sqrt{2}}{4} = \frac{3\times 1.414}{4} = 1.0605\approx 1.0606$
Hence option [C] is correct answer.