Aptitude Question ID: 107033

By how much does \sqrt{12}+\sqrt{18} exceed \sqrt{3}+\sqrt{2} ?
[A]2\left ( \sqrt{3}-\sqrt{2} \right )
[B]\sqrt{3}+2\sqrt{2}
[C]2\left ( \sqrt{3}+\sqrt{2} \right )
[D]\sqrt{2}-4\sqrt{3}

\mathbf{\sqrt{3}+2\sqrt{2}}
\because \left ( \sqrt{12}+\sqrt{18} \right )-\left ( \sqrt{3}+\sqrt{2} \right )
= (2\sqrt{3}-\sqrt{3})+(3\sqrt{2}-\sqrt{2})
= \sqrt{3}+2\sqrt{2}
Hence option [B] is correct answer.

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