# Aptitude Question ID: 106300

A is twice as fast as B and B is thrice as fast as C is. The journey covered by C in $1\frac{1}{2}$ hours will be covered by A in :
[A]15 minutes
[B]20 minutes
[C]30 minutes
[D]1 hour

15 minutes
Let speed of B = x km/hr
Speed of A = 2x km/hr
Speed of C $= \frac{x}{3}\ km/hr$
$\therefore \frac{Speed\ of\ A}{Speed\ of\ C} = \frac{2x}{\frac{x}{3}} = 6$
∴ Required Time $= \frac{1}{6}\ of \frac{3}{2}\ hours = \frac{1}{4}\ hours = 15\ minutes$
Hence option [A] is correct answer.