Aptitude Question ID: 106300

A is twice as fast as B and B is thrice as fast as C is. The journey covered by C in $latex 1\frac{1}{2}&s=1$ hours will be covered by A in :
[A]15 minutes
[B]20 minutes
[C]30 minutes
[D]1 hour

15 minutes
Let speed of B = x km/hr
Speed of A = 2x km/hr
Speed of C $latex = \frac{x}{3}\ km/hr&s=1$
$latex \therefore \frac{Speed\ of\ A}{Speed\ of\ C} = \frac{2x}{\frac{x}{3}} = 6&s=1$
∴ Required Time $latex = \frac{1}{6}\ of \frac{3}{2}\ hours = \frac{1}{4}\ hours = 15\ minutes&s=1$
Hence option [A] is correct answer.


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