A and B together can do a piece of work in 5 days and A alone can do it in 8 days, then B alone can do the same piece of work in :
A and B together can do a piece of work in 5 days and A alone can do it in 8 days, then B alone can do the same piece of work in :
[A]$latex 16\tfrac{4}{5}days&s=1$
[B]$latex 13\tfrac{1}{3}days&s=1$
[C]$latex 12\tfrac{3}{5}days&s=1$
[D]$latex 11\tfrac{1}{3}days&s=1$
$latex 13\tfrac{1}{3}days&s=1$
(A + B)’s 1 day’s work $latex =\frac{1}{5}&s=1$
A’s 1 day’s work $latex =\frac{1}{8}&s=1$
∴ B’s 1 day’s work $latex =\frac{1}{5}-\frac{1}{8}=\frac{8-5}{40}=\frac{3}{40}&s=1$
∴ B alone will complete the work in $latex \frac{40}{3}=13\tfrac{1}{3}\ days&s=1$.
Hence option [B] is correct answer.