Quantitative Aptitude Questions and Answers section on “Time and Distance” with solution and explanation for competitive examinations such as CAT, MBA, SSC, Bank PO, Bank Clerical and other examinations.

# Time and Distance

A man crosses a road 250 meters wide in 75 seconds. His speed in km/hr is:

[A]12.5

[B]15

[C]10

[D]12

**12**

$latex Speed = \frac{Distance }{Time}=\frac{250}{75}&s=1$

$latex =\frac{10}{3}m/s=\frac{10}{3}\times \frac{18}{5}km/hr&s=1$

$latex =2\times 6 km/hr= 12 km/hr$

Hence option [D] is the right answer.

An aeroplane covers a certain distance at a speed of 240 km/hour in 5 hours. To cover the same distance in $latex 1\frac{2}{3}$ hours, it must travel at a speed of :

[A]300 km/hr

[B]600 km/hr

[C]720 km/hr

[D]360 km/hr

**720 km./hr.**

Let the required speed is x km/hr

Then, $latex 240\times 5=\frac{5}{3}\times x$

x=720 km/hr.

Option [C] is the right answer.

An athlete runs 200 meters race in 24 seconds. His speed (in km/hr) is :

[A]28.5

[B]30

[C]24

[D]20

**30**

$latex Speed = \frac{Distance }{Time}=\frac{200}{24}m/s&s=1$

$latex =>\frac{200}{24}m/s=\frac{200}{24}\times \frac{18}{5}=30 km/hr&s=1$

Hence option [B] is the right answer.

A car travelling at a speed of 40 km/hour can complete a journey in 9 hours. How long will it take to travel the same distance at 60 km/hour?

[A]4 hours

[B]4.5 hours

[C]3 hours

[D]6 hours

**6 hours**

Total distance covered = speed $latex \times$ Time

=40$latex \times$9 = 360km/hr

The required time at 60 kmph = 360$latex \div$60=6 hours.

Hence option [D] is the right answer.

A car goes 10 meters in a second. Find its speed in km/hour.

[A]32

[B]48

[C]36

[D]40

**36**

Speed of car = 10 m/s

Required speed in kmph = $latex \frac{10\times 18}{5}=36km/hr&s=1$

Hence option [C] is the right answer.

A train is travelling at the rate of 45km/hr. How many seconds it will take to cover a distance of $latex \frac{4}{5}&s=1$km?

[A]90 sec.

[B]120 sec.

[C]64 sec.

[D]36 sec.

**64 sec.**

Time taken =

$latex = \frac{Distance}{Time}&s=1$

$latex = \frac{\frac{4}{5}}{45} hour = \frac{4\times 60\times 60}{5\times 45}sec.&s=1$

$latex = 64 sec.$

Hence option [C] is the right answer.

A man walking at the rate of 5 km/hr. crosses a bridge in 15 minutes. The length of the bridge (in meters) is:

[A]1000 m

[B]1250 m

[C]600 m

[D]750 m

**1250 m**

Speed of the man = 5 km/hr

$latex = 5\times \frac{1000}{60}m/min = \frac{250}{3}m/min&s=1$

Time taken to cross the bridge = 15 minutes

Length of the bridge = Speed $latex \times$ Time

$latex = \frac{250}{3}\times 15m = 1250m&s=1$

Hence option [B] is the right answer.

A man travelled a certain distance by train at the rate of 25 kmph. and walked back at the rate of 4 kmph. If the whole journey took 5 hours 48 minutes, the distance was:

[A]15 km

[B]20 km

[C]25 km

[D]30 km

**20 km**

Let the distance be x km.

Total time = 5 hours 48 minutes

$latex = 5+\frac{48}{60} = \left ( 5+\frac{4}{5} \right )hours&s=1$

$latex = \frac{29}{5}hours&s=1$

$latex \therefore \frac{x}{25}+\frac{x}{4} = \frac{29}{5}&s=1$

$latex => \frac{4x+25x}{100} = \frac{29}{5}&s=1$

$latex => 5\times 29x = 29\times 100$

$latex => x = \frac{29\times 100}{5\times 29} = 20km.&s=1$

Hence option [B] is the right answer.

A boy goes to his school from his house at a speed of 3 km/hr and returns at a speed of 2 km/hr. If he takes 5 hours in going and coming, the distance between his house and school is:

[A]6.5 km

[B]5.5 km

[C]5 km

[D]6 km

**6 km**

Let the required distance be x km.

Then,

$latex \frac{x}{3}+\frac{x}{2} = 5&s=1$

$latex => \frac{2x+3x}{6} = 5&s=1$

$latex => 5x = 6 \times 5$

$latex \therefore x = \frac{6\times 5}{5} = 6 km.&s=1$

Hence option [D] is the right answer.

A boy runs 20 km in 2.5 hours. How long will he take to run 32 km at double the previous speed?

[A]5 hours

[B]$latex 4\frac{1}{2}&s=1$

[C]2 hours

[D]$latex 2\frac{1}{2}&s=1$

**2 hours**

The boy covers 20 km in 2.5 hours.

$latex => speed = \frac{20}{2.5} = 8 km/hr.&s=1$

New speed = 16 km/hr

∴ Time $latex = \frac{32}{16} = 2 hours.&s=1$

Hence option [C] is the right answer.