If ABC is an equilateral triangle and D is a point on BC such that AD ⊥ BC, then :

If ABC is an equilateral triangle and D is a point on BC such that AD ⊥ BC, then :
[A]AB : BD = 2 : 1
[B]AB : BD = 1 : 2
[C]AB : BD = 1 : 1
[D]AB : BD = 3 : 2

AB : BD = 2 : 1
Let AB = 2x units
=> BD=DC = x units
∴ AB : BD = 2 : 1
Hence option [C] is the right answer.

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